73. (A) When a ray of light passes from air to glass, the angle of deviation $\delta$ decreases as the angle of incidence $i$ increases beyond a certain value.
(R) The refractive index $\mu = \frac{\sin i}{\sin r}$ remains constant for a given pair of media, but the relationship between $i$ and $r$ becomes non-linear at higher angles of incidence.
Key Concept: Refraction, Angle of Deviation, Refractive Index
a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
First, analyze the assertion (A): The angle of deviation $\delta = i - r$. Initially, as $i$ increases, $r$ also increases, but not proportionally due to Snell's law ($\mu = \frac{\sin i}{\sin r}$). For small angles, $\delta$ increases with $i$, but beyond a certain point (when $i$ is large), the increase in $r$ slows down, causing $\delta$ to decrease. Thus, (A) is true.
Next, consider the reason (R): The refractive index $\mu$ is indeed constant for a given pair of media, but the relationship between $i$ and $r$ is governed by $\sin i / \sin r = \mu$, which is non-linear. This non-linearity explains why $\delta$ behaves as described in (A). Therefore, (R) is true and correctly explains (A).
Your Answer is correct.
a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
First, analyze the assertion (A): The angle of deviation $\delta = i - r$. Initially, as $i$ increases, $r$ also increases, but not proportionally due to Snell's law ($\mu = \frac{\sin i}{\sin r}$). For small angles, $\delta$ increases with $i$, but beyond a certain point (when $i$ is large), the increase in $r$ slows down, causing $\delta$ to decrease. Thus, (A) is true.
Next, consider the reason (R): The refractive index $\mu$ is indeed constant for a given pair of media, but the relationship between $i$ and $r$ is governed by $\sin i / \sin r = \mu$, which is non-linear. This non-linearity explains why $\delta$ behaves as described in (A). Therefore, (R) is true and correctly explains (A).