Key Concept: Shells, Valency, and Electronic Configuration
b) Valency = 2, Group = 16, Period = 4
[Solution Description]
Atomic number of X is 34. First, let's write the electronic configuration step by step. The maximum number of electrons in each shell is given by $2n^2$, where $n$ is the shell number. For K-shell ($n = 1$): $2 \times 1^2 = 2$ electrons. L-shell ($n = 2$): $2 \times 2^2 = 8$ electrons. M-shell ($n = 3$): $2 \times 3^2 = 18$ electrons. N-shell ($n = 4$): $2 \times 4^2 = 32$ electrons.
For atomic number 34, the electronic configuration is:
$K = 2, L = 8, M = 18, N = 6$.
The total adds up to $2 + 8 + 18 + 6 = 34$.
Number of shells = 4 (K, L, M, N). So, it belongs to the 4th period.
Outermost shell (N-shell) has 6 electrons. Valency = $8 - 6 = 2$.
Group number = Number of valence electrons for non-transition elements. Here, Group = 16 (since valence electrons are 6).
Final answer: Valency = 2, Group = 16, Period = 4.
Your Answer is correct.
b) Valency = 2, Group = 16, Period = 4
[Solution Description]
Atomic number of X is 34. First, let's write the electronic configuration step by step. The maximum number of electrons in each shell is given by $2n^2$, where $n$ is the shell number. For K-shell ($n = 1$): $2 \times 1^2 = 2$ electrons. L-shell ($n = 2$): $2 \times 2^2 = 8$ electrons. M-shell ($n = 3$): $2 \times 3^2 = 18$ electrons. N-shell ($n = 4$): $2 \times 4^2 = 32$ electrons.
For atomic number 34, the electronic configuration is:
$K = 2, L = 8, M = 18, N = 6$.
The total adds up to $2 + 8 + 18 + 6 = 34$.
Number of shells = 4 (K, L, M, N). So, it belongs to the 4th period.
Outermost shell (N-shell) has 6 electrons. Valency = $8 - 6 = 2$.
Group number = Number of valence electrons for non-transition elements. Here, Group = 16 (since valence electrons are 6).
Final answer: Valency = 2, Group = 16, Period = 4.